WAEC 2018/2019 CHEMISTRY OBJ & ESSAY QUESTIONS & ANSWERS/RUNZ



Chemistry THEORY :
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1ai)
Fermentation is the process in which a substance breaks down into a simpler substance. Microorganisms like yeast and bacteria usually play a role in thefermentation process, creating beer, wine, bread, kimchi, yogurt and other foods. Fermentation comes from the Latin word fermentare, meaning “to leaven.

(1aii)
Zymase

(1b)
-The strength of an acid
-The PH of the solution

(1c)
Fe+H2SO4->FESO4 + H2
H2SO4=10cm^3
Concentration=1mol/dm^3
Amount=Vol * Concentration
=10/100 1
=0.01mol
1mol=56g
0.01mol=56 0.01
=0.56g
Mass of unreacted=5-0.056
=4.44g

1d===

1e) A catalyst increases the rate of reaction by lowering the activation energy of the reaction

1fi) CH3COOH + NH3 → CH3COONH2 + H2(g)
fii)
Ethanamide

1g)
i. It has a light weight
ii. It has resistance to rusting
iii. It has a greater tensile strenght
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(2ai)
Collision theory states that the rate of a reaction depends on the rate of collision of the reactant molecules. Hence effective collision determines the rate of the reaction because it is the collision that leads to the formation of a product.

(2aii)
When the rate of collision increases, the rate at which molecules collide with each other will also increase thereby making the kinetic energy of the molecules to also increase. The temperature will also increase because temperature is a measure of average kinetic energy.


(2bi)
Draw your diagram
(2bii)
C2H5OH + 3O2 —->2CO2 + 3H2O
1mole of ethanol = 3moles of O2
2.5moles of ethanol will require 3 × 2.5/1 = 7.5moles of O2.
but 1 mole of gas = 22.4dm3
7.5moles = 7.5 × 22.4 = 168dm3 of O2.

(2Ci)
Esterification is the formation of an Ester by the reaction between Alkanol and an acid.

(2cii) Two uses of alkanols
(i) They are used as solvents for cellulose
(ii) They are uses in making perfumes and cosmetics.
(iii) They are used for quick drying of paints and nail varnishes.

(2ciii)
Sodium Ethanoate

(2di)
Tin

(2dii )
This is because the galvanized plate is corrosion-resistant. It has a protective coating which prevents further oxidation of the metal.

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(3ai)
H H H H H
| | | | |
H-C-C-C-C-C-C=C-H Heptene
| | | | | |
H H H H H H

(3aii)
The sixth member of Allene C7H14 =
7(molecular mass of carbon) + 14(molecular mass of H)
= 7(12) + 14(1)
= 84 + 14 = 98gmol-¹

(3aiii)
-Cracking is the breaking down of higher molecules into smaller molecules while reforming is the change in the functional group or activity of the compound.
-In cracking more than one product or component is formed. But in reforming one product can still be gotten.

(3bi)
Enthalpy of Neutralization change is the heat change which offers when one mole of H+ from an acid reacts with one mole of OH- from an alkali to form one mole of water.

(3bii)
Weigh about 100cm³ of dil HCL(aq) and that of KOH(aq) of equal volume and put each into a glass calorimeter. The temperature of the two Solutions are taken. The mean volume of the temperature of the acid and base taken. Then quickly transfer the alkali to the acid, turn and take the final temperature of the solution. Record the mass of the mixture. Find the temperature difference.
Total heat covered = mass × specific heat capacity × temperature change.

(3ci)
I – copper
II – silver

(3cii)
Because silver is below copper in the electrochemical series.

(3ciii)
Oxidation – anode
Reduction – Cathode

4ai)


4aii)
Na2SO3(aq) + 2HCl(aq)—–>2Nacl(aq)+H2O(s)+SO2(q)

4aiii)
dry the gas evolved by passing it through H2SO4 and collect it by downward delivery

4aiv)
because it is denser than air

4bi)
Dalton’s law of partial pressure states that in a mixture of gases, which do not react chemically together, a gas will exert a partial pressure, which is the pressure, it will exert if it is kept alone in the vessel.

4bii)
T1=12degree = 285k
P1=690mm Hg
V1=30cm^3
T2=273k
P2=760mmhg
V2=?
Using the general gas law
V1P1/T1 = V2P2/T2
V2=30 690273/285*760
V2=261cm^3
V2=26cm^3

4ci)
Cl2(q)+H2O(i)——>HCL(aq)+HOCL(aq)

4cii)
litmus turn red because of the presence of the acid HCL.

4di)
chlorine bromine iodine/increasing boiling point.

4dii)
because water has two(2)ion pairs of electrons as compared to ammonia which has one.


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(5ai )
Na2S2O3 ===> 2+2x+6=0
2x=6-2=4
X=4/2
X=2
The oxidation number of sulphur is 2

(5aii)
Rhombic & monoclinic

(5aiii )
-Both are tetravalent
-both are allotrope of carbon.

(5bi)
CO2 & Chloroflorocarbon.

(5bii)
There is increase in sun radiation reaching the
earths surface ie Global warming

(5biii )
ThunderStorm.

(5iv)
I 2KNo3 —-> 2KNO3 + O2
II AgNo3 —> 2Ag + 2NO

(5ci)
Calcium chloride in a solution can give rise to
crystal using filteration & evaporation to dryness .
The sol is filtered into filtrate & residue b4
evaporation to dryness takes place.

(5cii)
– Because of presence of hydrogen bonding in
NH3
-Because Iodine as higher molecular mass than
chlorine

(5di)
Mol of Nacl = Mass/MM
= 5.85/58.01
= 0.1mol
From the equation
2mol of Nacl gives 2mol of HCL, 0.1mol of Nacl
gives 0.1mol of Hcl
Vol of Hcl = 0.1 x 22.4 = 2.24mol/dm^3
Typing…..

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1 Response to "WAEC 2018/2019 CHEMISTRY OBJ & ESSAY QUESTIONS & ANSWERS/RUNZ"

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